8y-20y^2=5y

Solution for 8y-20y^2=5y equation:

8y-20y^2=5y

We move all terms to the left:

8y-20y^2-(5y)=0

We add all the numbers together, and all the variables

-20y^2+3y=0

a = -20; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-20)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-20}=\frac{-6}{-40}
=3/20
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-20}=\frac{0}{-40}
=0
$